X-0,04x^2+3=0

Solution for X-0,04x^2+3=0 equation:

X-0.04X^2+3=0

a = -0.04; b = 1; c = +3;
Δ = b2-4ac
Δ = 12-4·(-0.04)·3
Δ = 1.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1.48}}{2*-0.04}=\frac{-1-\sqrt{1.48}}{-0.08}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1.48}}{2*-0.04}=\frac{-1+\sqrt{1.48}}{-0.08}
$